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Beliebt Geometry >

leitkurve y^2+6y-2x+13=0

Lösung

leitkurve

y^{2} + 6 y - 2 x + 13 = 0

Lösung

x = \frac{3}{2}

Schritte zur Lösung

Rewrite

y^{2} + 6 y - 2 x + 13 = 0

in the standard form

4 \cdot \frac{1}{2} (x - 2) = (y - (- 3))^{2}

(h, k) = (2, - 3), p = \frac{1}{2}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, - 3)

x-coordinate

x = 2 - p

x = 2 - \frac{1}{2}

Fasse zusammen

x = \frac{3}{2}

Graph

Beliebte Beispiele

scheitelpunkte (x^2)/(49)+(y^2)/(16)=1

v er t i ces \frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

scheitelpunkte f(x)=x^2+2x-8

v er t i ces f (x) = x^{2} + 2 x - 8

(x^2}{36}-\frac{y^2)/9 =1

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

a x i s y = x^{2}

scheitelpunkte f(x)=x^2-4x-12

v er t i ces f (x) = x^{2} - 4 x - 12