4x^2-4x-8y+9=0

Lösung

4 x^{2} - 4 x - 8 y + 9 = 0

(h, k) = (\frac{1}{2}, 1), p = \frac{1}{2}

Schritte zur Lösung

4 x^{2} - 4 x - 8 y + 9 = 0

Rewrite

4 x^{2} - 4 x - 8 y + 9 = 0

in the standard form

4 \cdot \frac{1}{2} (y - 1) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, 1), p = \frac{1}{2}

x^{2} - 6 x - 12 y - 51 = 0

x^{2} = C y

x^{2} + 4 x + 3 y = 0

6 x^{2} = - 24 y

(y + 1.5)^{2} = 4 (x - 2)