What is x^2-18x+81+y^2=x^2-10x+25+y+12y+36 ?

The solution to x^2-18x+81+y^2=x^2-10x+25+y+12y+36 is Parabola with (h,k)=(-89/32 , 13/2),p=2

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x^2-18x+81+y^2=x^2-10x+25+y+12y+36

x^{2} - 18 x + 81 + y^{2} = x^{2} - 10 x + 25 + y + 12 y + 36

(h, k) = (- \frac{89}{32}, \frac{13}{2}), p = 2

Solution steps

x^{2} - 18 x + 81 + y^{2} = x^{2} - 10 x + 25 + y + 12 y + 36

Rewrite

x^{2} - 18 x + 81 + y^{2} - x^{2} + 10 x - 25 - y - 12 y - 36 = 0

in the standard form

4 \cdot 2 (x - (- \frac{89}{32})) = (y - \frac{13}{2})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{89}{32}, \frac{13}{2}), p = 2

x^{2} = 60 y

x + 8 = y^{2}

x + 9 = y^{2}

2 x^{2} - 3 y = 1

2 x^{2} - 7 x + K (x) = 0

What is x^2-18x+81+y^2=x^2-10x+25+y+12y+36 ?
The solution to x^2-18x+81+y^2=x^2-10x+25+y+12y+36 is Parabola with (h,k)=(-89/32 , 13/2),p=2