What is (x-3/2)^2=-7(2)(y-1) ?

The solution to (x-3/2)^2=-7(2)(y-1) is Parabola with (h,k)=(3/2 ,1),p=-7/2

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(x-3/2)^2=-7(2)(y-1)

(x - \frac{3}{2})^{2} = - 7 (2) (y - 1)

(h, k) = (\frac{3}{2}, 1), p = - \frac{7}{2}

Solution steps

(x - \frac{3}{2})^{2} = - 7 \cdot 2 (y - 1)

Rewrite

(x - \frac{3}{2})^{2} = - 7 \cdot 2 (y - 1)

in the standard form:

4 (- \frac{7}{2}) (y - 1) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, 1), p = - \frac{7}{2}

x^{2} + 4 x + 12 y - 56 = 0

x^{2} - 2 x + 1 + y^{2} = x^{2} - 2 x + y^{2} - 2 y + 1

- y = x^{2}

x^{2} - 2 x + m (x) - 2 = 0

x^{2} = 8 (y - 2)

What is (x-3/2)^2=-7(2)(y-1) ?
The solution to (x-3/2)^2=-7(2)(y-1) is Parabola with (h,k)=(3/2 ,1),p=-7/2