What is 1=(3x^2+5x)/(h(x)) ?

The solution to 1=(3x^2+5x)/(h(x)) is Parabola with (h,k)=(-5/6 ,-25/12),p= 1/12

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1=(3x^2+5x)/(h(x))

1 = \frac{3 x ^{2} + 5 x}{h ( x )}

(h, k) = (- \frac{5}{6}, - \frac{25}{12}), p = \frac{1}{12}

Solution steps

1 = \frac{3 x ^{2} + 5 x}{y}

Rewrite

1 - \frac{3 x ^{2} + 5 x}{y} = 0

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{25}{12})) = (x - (- \frac{5}{6}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{6}, - \frac{25}{12}), p = \frac{1}{12}

x - 4 y^{2} \geq 0.2 - x - 7

x^{2} = y - 7

x^{2} - 10 x + 6 y = 1

x^{2} + (y - 4) 2 = 25

\frac{x ^{2}}{9} + \frac{y}{16} = 1

What is 1=(3x^2+5x)/(h(x)) ?
The solution to 1=(3x^2+5x)/(h(x)) is Parabola with (h,k)=(-5/6 ,-25/12),p= 1/12