What is 36y^2+2+72x-132y-239=0 ?

The solution to 36y^2+2+72x-132y-239=0 is Parabola with (h,k)=(179/36 , 11/6),p=-1/2

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36y^2+2+72x-132y-239=0

36 y^{2} + 2 + 72 x - 132 y - 239 = 0

(h, k) = (\frac{179}{36}, \frac{11}{6}), p = - \frac{1}{2}

Solution steps

36 y^{2} + 2 + 72 x - 132 y - 239 = 0

Rewrite

36 y^{2} + 2 + 72 x - 132 y - 239 = 0

in the standard form

4 (- \frac{1}{2}) (x - \frac{179}{36}) = (y - \frac{11}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{179}{36}, \frac{11}{6}), p = - \frac{1}{2}

x = y^{2} + 6 y + 4

f (x) = 4 x^{2} - x + 3.2 f (x)

y = - x^{2} - 12 x - 36

y^{2} = 5 x - 14

x = \frac{1}{3} y^{2}

What is 36y^2+2+72x-132y-239=0 ?
The solution to 36y^2+2+72x-132y-239=0 is Parabola with (h,k)=(179/36 , 11/6),p=-1/2