What is x= 17/256 (y-0)^2-32 ?

The solution to x= 17/256 (y-0)^2-32 is Parabola with (h,k)=(-32,0),p= 64/17

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x= 17/256 (y-0)^2-32

x = \frac{17}{256} (y - 0)^{2} - 32

(h, k) = (- 32, 0), p = \frac{64}{17}

Solution steps

x = \frac{17}{256} (y - 0)^{2} - 32

Rewrite

x = \frac{17}{256} (y - 0)^{2} - 32

in the standard form:

4 \cdot \frac{64}{17} (x - (- 32)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 32, 0), p = \frac{64}{17}

\frac{a + 5}{b} = \frac{a - 5}{b} + \frac{b + 5}{a}

x^{2} + 4 y + 8 = 0

y = x^{2} - 3 \frac{1}{2}

3 x^{2} - y = 4

3 x^{2} - y = 6

What is x= 17/256 (y-0)^2-32 ?
The solution to x= 17/256 (y-0)^2-32 is Parabola with (h,k)=(-32,0),p= 64/17