What is 6x^2+7x+h(x)=0 ?

The solution to 6x^2+7x+h(x)=0 is Parabola with (h,k)=(-7/12 , 49/24),p=-1/24

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6x^2+7x+h(x)=0

6 x^{2} + 7 x + h (x) = 0

(h, k) = (- \frac{7}{12}, \frac{49}{24}), p = - \frac{1}{24}

Solution steps

6 x^{2} + 7 x + y = 0

Rewrite

6 x^{2} + 7 x + y = 0

in the standard form

4 (- \frac{1}{24}) (y - \frac{49}{24}) = (x - (- \frac{7}{12}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{12}, \frac{49}{24}), p = - \frac{1}{24}

x^{2} + y - 3 x + 1 = 0

(x - 2)^{2} = 10 (y - 3)

(x + 3)^{2} = 4 (y - 4)

x^{(2)} = 8 y

x^{2} - 10 x + 2 y = 0

What is 6x^2+7x+h(x)=0 ?
The solution to 6x^2+7x+h(x)=0 is Parabola with (h,k)=(-7/12 , 49/24),p=-1/24