What is x^2y^0+7xy^0+9y=0 ?

The solution to x^2y^0+7xy^0+9y=0 is Parabola with (h,k)=(-7/2 , 49/36),p=-9/4

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x^2y^0+7xy^0+9y=0

x^{2} y^{0} + 7 x y^{0} + 9 y = 0

(h, k) = (- \frac{7}{2}, \frac{49}{36}), p = - \frac{9}{4}

Solution steps

x^{2} y^{0} + 7 x y^{0} + 9 y = 0

Rewrite

x^{2} y^{0} + 7 x y^{0} + 9 y = 0

in the standard form

4 (- \frac{9}{4}) (y - \frac{49}{36}) = (x - (- \frac{7}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{2}, \frac{49}{36}), p = - \frac{9}{4}

y < 2 x^{2} - 2

x^{2} - 4 y - 12 x + 68 = 0

x^{2} - 8 x + 8 y + 16 = 0

y = x^{2} + 12 x + 16

- y = 9 - x^{2}

What is x^2y^0+7xy^0+9y=0 ?
The solution to x^2y^0+7xy^0+9y=0 is Parabola with (h,k)=(-7/2 , 49/36),p=-9/4