2x^2+8x+3y-5=0

Lösung

2 x^{2} + 8 x + 3 y - 5 = 0

(h, k) = (- 2, \frac{13}{3}), p = - \frac{3}{8}

Schritte zur Lösung

2 x^{2} + 8 x + 3 y - 5 = 0

Rewrite

2 x^{2} + 8 x + 3 y - 5 = 0

in the standard form

4 (- \frac{3}{8}) (y - \frac{13}{3}) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, \frac{13}{3}), p = - \frac{3}{8}

3 y^{2} - 3 x = 0

x^{2} = - y + 5

x^{2} \geq - 2 y

(y + 3)^{2} = - 8 (x - 4)

p y^{2} = - 12 x