What is g(x)(a+b)=x^2-4 ?

The solution to g(x)(a+b)=x^2-4 is Parabola with (h,k)=(0,-4/(a+b)),p=(a+b)/4

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g(x)(a+b)=x^2-4

g (x) (a + b) = x^{2} - 4

(h, k) = (0, - \frac{4}{a + b}), p = \frac{a + b}{4}

Solution steps

y (a + b) = x^{2} - 4

Rewrite

y (a + b) = x^{2} - 4

in the standard form:

4 \cdot \frac{a + b}{4} (y - (- \frac{4}{a + b})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{4}{a + b}), p = \frac{a + b}{4}

y^{2} + 6 y - 2 x + 5 = 0

9 x^{2} - 12 x + m (x) = 0

- x^{2} + 7 x + y + 30 < 0

y^{2} = \frac{3}{2} x

x^{2} = 8 p (x)

What is g(x)(a+b)=x^2-4 ?
The solution to g(x)(a+b)=x^2-4 is Parabola with (h,k)=(0,-4/(a+b)),p=(a+b)/4