What is -f(x)=3(x)^2+3(x)-4 ?

The solution to -f(x)=3(x)^2+3(x)-4 is Parabola with (h,k)=(-1/2 , 19/4),p=-1/12

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-f(x)=3(x)^2+3(x)-4

- f (x) = 3 (x)^{2} + 3 (x) - 4

(h, k) = (- \frac{1}{2}, \frac{19}{4}), p = - \frac{1}{12}

Solution steps

- y = 3 x^{2} + 3 x - 4

Rewrite

- y = 3 x^{2} + 3 x - 4

in the standard form

4 (- \frac{1}{12}) (y - \frac{19}{4}) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, \frac{19}{4}), p = - \frac{1}{12}

x^{2} - 2 x + 8 y - 7 = 0

y > x^{2} + 4 x - 12

x (2 x - 5) = p (x) - 4

x^{2} - 4 x - 6 y - 36 = 0

x = (y - 2)^{2} - 3

What is -f(x)=3(x)^2+3(x)-4 ?
The solution to -f(x)=3(x)^2+3(x)-4 is Parabola with (h,k)=(-1/2 , 19/4),p=-1/12