(x^2}{36}+\frac{y^2)/4 =1

Lösung

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

(h, k) = (0, 0), a = 6, b = 2

Schritte zur Lösung

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 2

v er t i ces f (x) = x^{2} - 10 x + 24

v er t i ces \frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

v er t i ces f (x) = x^{2} - 8 x + 12

a sy m pt o t es \frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

v er t i ces \frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1