What is (k(x))/(x+sqrt(2))>= (x^2)/(x+sqrt(2)) ?

The solution to (k(x))/(x+sqrt(2))>= (x^2)/(x+sqrt(2)) is Parabola with (h,k)=(0,0),p= 1/4

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(k(x))/(x+sqrt(2))>= (x^2)/(x+sqrt(2))

\frac{k ( x )}{x + 2} \geq \frac{x ^{2}}{x + 2}

(h, k) = (0, 0), p = \frac{1}{4}

Solution steps

\frac{y}{x + 2} \geq \frac{x ^{2}}{x + 2}

Rewrite

\frac{y}{x + 2} - \frac{x ^{2}}{x + 2} \geq 0

in the standard form

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

y + x^{2} < 2

x = y^{2} - 8

x + 8 = \frac{1}{12} (y + 2)^{2}

y + 3 x = x^{2}

(y - 5)^{2} = 16 x

What is (k(x))/(x+sqrt(2))>= (x^2)/(x+sqrt(2)) ?
The solution to (k(x))/(x+sqrt(2))>= (x^2)/(x+sqrt(2)) is Parabola with (h,k)=(0,0),p= 1/4