2x+y=x^2

Lösung

2 x + y = x^{2}

(h, k) = (1, - 1), p = \frac{1}{4}

Schritte zur Lösung

2 x + y = x^{2}

Rewrite

2 x + y = x^{2}

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 1), p = \frac{1}{4}

y^{2} + 2 y - 4 x = 7

x^{2} = - 7 y

y^{2} - 3 y + 5 x + 2 = 0

(x - 3)^{2} = - 4 (y - 5)

x^{2} = - 12 (y - 3)