x^2<y

Lösung

x^{2} < y

(h, k) = (0, 0), p = \frac{1}{4}

Schritte zur Lösung

x^{2} < y

Rewrite

x^{2} < y

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

x - 4 y^{2} = 0

x + 2 y^{2} + 4 y - 5 = 0

a x + b y^{2} = c

(x + 3)^{2} + (y - 0) = 16

y + 16 = x^{2} + 8