What is the eccentricity 2x^2-4y^2=1 ?

The eccentricity 2x^2-4y^2=1 is sqrt(3/2)

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eccentricity 2x^2-4y^2=1

eccentricity

2 x^{2} - 4 y^{2} = 1

\frac{3}{2}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

2 x^{2} - 4 y^{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = \frac{1}{2}, b = \frac{1}{2}

= \frac{( \frac{1}{2} ) ^{2} + ( \frac{1}{2} ) ^{2}}{\frac{1}{2}}

Refine

= \frac{3}{2}

9 x^{2} - 4 y^{2} - 18 x - 16 y - 43 = 0

225 x^{2} - 64 y^{2} = 14400

\frac{x ^{2}}{4} - \frac{y ^{2}}{6} = - 1

x^{2} + y^{2} - 2 x + 8 y - 47 = 0

\frac{( x ^{2} )}{73} - \frac{( y ^{2} )}{19} = 1

What is the eccentricity 2x^2-4y^2=1 ?
The eccentricity 2x^2-4y^2=1 is sqrt(3/2)