exzentrizität y^2-4y-4x^2+13=0

Lösung

exzentrizität

y^{2} - 4 y - 4 x^{2} + 13 = 0

5

Dezimale

2.23606 \dots

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

y^{2} - 4 y - 4 x^{2} + 13 = 0 :

Right-left Hyperbola with

(h, k) = (0, 2), a = \frac{3}{2}, b = 3

= \frac{( \frac{3}{2} ) ^{2} + 3 ^{2}}{\frac{3}{2}}

Fasse zusammen

= 5

ecce n t r i c i t y + \frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

ecce n t r i c i t y 9 y^{2} - 4 x^{2} = 36

ecce n t r i c i t y 25 x^{2} + 56476 x - 25 y^{2} - 3 y = 48838

ecce n t r i c i t y \frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

ecce n t r i c i t y \frac{x ^{2}}{40} - \frac{y ^{2}}{174} = 1