What is the eccentricity (x^2)/(45)-(y^2)/(216)=1 ?

The eccentricity (x^2)/(45)-(y^2)/(216)=1 is sqrt(29/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity (x^2)/(45)-(y^2)/(216)=1

eccentricity

\frac{x ^{2}}{45} - \frac{y ^{2}}{216} = 1

\frac{29}{5}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{45} - \frac{y ^{2}}{216} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 35, b = 66

= \frac{( 3 5 ) ^{2} + ( 6 6 ) ^{2}}{3 5}

Refine

= \frac{29}{5}

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

49 x^{2} - 25 y^{2} - 686 x - 50 y + 2375 = 0

\frac{y ^{2}}{25} - \frac{( x + 1 ) ^{2}}{16} = 1

+ \frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

What is the eccentricity (x^2)/(45)-(y^2)/(216)=1 ?
The eccentricity (x^2)/(45)-(y^2)/(216)=1 is sqrt(29/5)