What is the eccentricity (y^2)/9-(x^2)/(16)=1 ?

The eccentricity (y^2)/9-(x^2)/(16)=1 is 5/3

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eccentricity (y^2)/9-(x^2)/(16)=1

eccentricity

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

\frac{5}{3}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 4

= \frac{3 ^{2} + 4 ^{2}}{3}

Refine

= \frac{5}{3}

\frac{x ^{2}}{25} - \frac{y ^{2}}{36} = 1

x^{2} - 4 y^{2} - 4 x + 8 y - 16 = 0

\frac{( x - 2 ) ^{2}}{5} - \frac{( y + 1 ) ^{2}}{9} = 1

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1

x^{2} - y^{2} = 25

What is the eccentricity (y^2)/9-(x^2)/(16)=1 ?
The eccentricity (y^2)/9-(x^2)/(16)=1 is 5/3