exzentrizität 0=-400/9 x^2+16y^2+400

Lösung

exzentrizität

0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400

\frac{34}{3}

Dezimale

1.94365 \dots

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 5

= \frac{3 ^{2} + 5 ^{2}}{3}

Fasse zusammen

= \frac{34}{3}

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