What is the eccentricity 4x^2-y^2-24x-4y+28=0 ?

The eccentricity 4x^2-y^2-24x-4y+28=0 is square root of 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity 4x^2-y^2-24x-4y+28=0

eccentricity

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

5

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0 :

Right-left Hyperbola with

(h, k) = (3, - 2), a = 1, b = 2

= \frac{1 ^{2} + 2 ^{2}}{1}

Refine

= 5

9 y^{2} - x^{2} + 2 x + 54 y + 62 = 0

4 x^{2} - 25 y^{2} + 100 y = 200

9 y^{2} - 16 x^{2} = 144

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

What is the eccentricity 4x^2-y^2-24x-4y+28=0 ?
The eccentricity 4x^2-y^2-24x-4y+28=0 is square root of 5