What is the center 4y^2-9x^2+16y+18x=29 ?

The center 4y^2-9x^2+16y+18x=29 is (1,-2)

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center 4y^2-9x^2+16y+18x=29

center

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

(1, - 2)

Solution steps

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

Rewrite

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 3, b = 2

And the center is:

(1, - 2)

16 y^{2} - 32 y - 9 x^{2} - 18 x = 137

\frac{x ^{2}}{25} - \frac{y ^{2}}{49} = 1

321 + 108 x - 9 x^{2} + 8 y + 4 y^{2} = 0

2 x^{2} - y^{2} - 2 y = - 5

- 6 x^{2} + 4 y^{2} + 6 x + 16 y - 1 = 0

What is the center 4y^2-9x^2+16y+18x=29 ?
The center 4y^2-9x^2+16y+18x=29 is (1,-2)