What is the center x^2-(y^2)/(25)=1 ?

The center x^2-(y^2)/(25)=1 is (0,0)

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center x^2-(y^2)/(25)=1

center

x^{2} - \frac{y ^{2}}{25} = 1

(0, 0)

Solution steps

x^{2} - \frac{y ^{2}}{25} = 1

Rewrite

x^{2} - \frac{y ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 5

And the center is:

(0, 0)

9 x^{2} - 16 y^{2} - 126 x + 160 y - 103 = 0

\frac{( x - h ) ^{2}}{64} - \frac{( y - k ) ^{2}}{9} = 1

\frac{x ^{2}}{6} - \frac{y ^{2}}{8} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{25} = 1

4 x^{2} - 3 y^{2} - 8 x - 8 = 0