What is the center ((x-5)^2)/4-((y+5)^2)/9 =1 ?

The center ((x-5)^2)/4-((y+5)^2)/9 =1 is (5,-5)

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center ((x-5)^2)/4-((y+5)^2)/9 =1

center

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 5 ) ^{2}}{9} = 1

(5, - 5)

Solution steps

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 5 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 5 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 5 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, - 5), a = 2, b = 3

And the center is:

(5, - 5)

x^{2} - y^{2} + 2 y = 0

25 y^{2} - 16 x^{2} - 400 = 0

9 x^{2} - 16 y^{2} = 144

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{5} = 1

What is the center ((x-5)^2)/4-((y+5)^2)/9 =1 ?
The center ((x-5)^2)/4-((y+5)^2)/9 =1 is (5,-5)