What is the center 4x^2-9y^2-36=0 ?

The center 4x^2-9y^2-36=0 is (0,0)

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center 4x^2-9y^2-36=0

center

4 x^{2} - 9 y^{2} - 36 = 0

(0, 0)

Solution steps

4 x^{2} - 9 y^{2} - 36 = 0

Rewrite

4 x^{2} - 9 y^{2} - 36 = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 2

And the center is:

(0, 0)

\frac{x ^{2}}{16} - \frac{y ^{2}}{36} = 1

x^{2} - 4 y^{2} - 20 x - 64 y - 172 = 0

- 9 x^{2} - 32 y = - 16 y^{2} + 128

\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

2 x^{2} - 2 y^{2} - 20 x + 16 y + 16 = 0