What is p(x)((x))/(x^2)-4x+4=0 ?

The solution to p(x)((x))/(x^2)-4x+4=0 is Parabola with (h,k)=(1/2 ,-1),p= 1/16

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p(x)((x))/(x^2)-4x+4=0

p (x) \frac{( x )}{x ^{2}} - 4 x + 4 = 0

(h, k) = (\frac{1}{2}, - 1), p = \frac{1}{16}

Solution steps

y \frac{x}{x ^{2}} - 4 x + 4 = 0

Rewrite

y \frac{x}{x ^{2}} - 4 x + 4 = 0

in the standard form

4 \cdot \frac{1}{16} (y - (- 1)) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, - 1), p = \frac{1}{16}

y^{2} - 8 x - 6 y + 17 = 0

(x - 4)^{2} = 12 (y - 5)

x + 7 = \frac{1}{36} (y + 3)^{2}

8 (y - 1) = - (x + 3)^{2}

y^{2} = 6 (x - 2)

What is p(x)((x))/(x^2)-4x+4=0 ?
The solution to p(x)((x))/(x^2)-4x+4=0 is Parabola with (h,k)=(1/2 ,-1),p= 1/16