What is the asymptotes of 10y^2-49x^2=490 ?

The asymptotes of 10y^2-49x^2=490 is y=(7x)/(sqrt(10)),\quad y=-(7x)/(sqrt(10))

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asymptotes of 10y^2-49x^2=490

asymptotes

10 y^{2} - 49 x^{2} = 490

y = \frac{7 x}{10}, y = - \frac{7 x}{10}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

10 y^{2} - 49 x^{2} = 490 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 7, b = 10

y = \frac{7}{10} (x - 0) + 0, y = - \frac{7}{10} (x - 0) + 0

Refine

y = \frac{7 x}{10}, y = - \frac{7 x}{10}

x^{2} - 4 y^{2} = 36

y^{2} - 9 x^{2} = 9

x^{2} - 2 y^{2} + 3 x + 4 y = 2

\frac{1}{4} (y + 5)^{2} - \frac{1}{16} (x + 1)^{2} = 1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{9} = 1

What is the asymptotes of 10y^2-49x^2=490 ?
The asymptotes of 10y^2-49x^2=490 is y=(7x)/(sqrt(10)),\quad y=-(7x)/(sqrt(10))