What is the asymptotes of-9x^2+8y^2+36x+48y=36 ?

The asymptotes of-9x^2+8y^2+36x+48y=36 is y= 3/(2sqrt(2))(x-2)-3,\quad y=-3/(2sqrt(2))(x-2)-3

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asymptotes of-9x^2+8y^2+36x+48y=36

asymptotes

- 9 x^{2} + 8 y^{2} + 36 x + 48 y = 36

y = \frac{3}{2 2} (x - 2) - 3, y = - \frac{3}{2 2} (x - 2) - 3

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

- 9 x^{2} + 8 y^{2} + 36 x + 48 y = 36 :

Up-down Hyperbola with

(h, k) = (2, - 3), a = 3, b = 22

y = \frac{3}{2 2} (x - 2) + (- 3), y = - \frac{3}{2 2} (x - 2) + (- 3)

x^{2} - y^{2} + 2 y = 2

5 x^{2} - 4 y^{2} - 20 x - 8 y = 4

4 x^{2} - 9 y^{2} = 144

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

4 x^{2} - 25 y^{2} + 100 y = 200

What is the asymptotes of-9x^2+8y^2+36x+48y=36 ?
The asymptotes of-9x^2+8y^2+36x+48y=36 is y= 3/(2sqrt(2))(x-2)-3,\quad y=-3/(2sqrt(2))(x-2)-3