What is the asymptotes of (y^2}{16}-\frac{x^2)/1 =1 ?

The asymptotes of (y^2}{16}-\frac{x^2)/1 =1 is y=4x,\quad y=-4x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of (y^2}{16}-\frac{x^2)/1 =1

asymptotes

\frac{y ^{2}}{16} - \frac{x ^{2}}{1} = 1

y = 4 x, y = - 4 x

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{16} - \frac{x ^{2}}{1} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 1

y = \frac{4}{1} (x - 0) + 0, y = - \frac{4}{1} (x - 0) + 0

Refine

y = 4 x, y = - 4 x

4 x^{2} - y^{2} = 2

4 x^{2} - y^{2} = 4

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y - 2 = 0

\frac{x ^{2}}{10} - \frac{y ^{2}}{90} = 1

\frac{y ^{2} - x ^{2}}{9} = 1

What is the asymptotes of (y^2}{16}-\frac{x^2)/1 =1 ?
The asymptotes of (y^2}{16}-\frac{x^2)/1 =1 is y=4x,\quad y=-4x