What is the asymptotes of ((x-1)^2)/4-((y+1)^2)/9 =1 ?

The asymptotes of ((x-1)^2)/4-((y+1)^2)/9 =1 is y= 3/2 (x-1)-1,\quad y=-3/2 (x-1)-1

Popular >

asymptotes of ((x-1)^2)/4-((y+1)^2)/9 =1

asymptotes

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

y = \frac{3}{2} (x - 1) - 1, y = - \frac{3}{2} (x - 1) - 1

Solution steps

y = \pm \frac{b}{a} (x - h) + k

Calculate Hyperbola properties

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (1, - 1), a = 2, b = 3

y = \frac{3}{2} (x - 1) + (- 1), y = - \frac{3}{2} (x - 1) + (- 1)

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

- 9 x^{2} + 4 y^{2} = 36

\frac{y ^{2}}{25} - x^{2} = 1

16 y^{2} - x^{2} + 2 x + 64 y + 47 = 0

y^{2} - x^{2} = \frac{1}{25}

What is the asymptotes of ((x-1)^2)/4-((y+1)^2)/9 =1 ?
The asymptotes of ((x-1)^2)/4-((y+1)^2)/9 =1 is y= 3/2 (x-1)-1,\quad y=-3/2 (x-1)-1