What is the asymptotes of (y^2)/4-(x^2)/(16)=1 ?

The asymptotes of (y^2)/4-(x^2)/(16)=1 is y= x/2 ,\quad y=-x/2

Popular >

asymptotes of (y^2)/4-(x^2)/(16)=1

asymptotes

\frac{y ^{2}}{4} - \frac{x ^{2}}{16} = 1

y = \frac{x}{2}, y = - \frac{x}{2}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{16} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 4

y = \frac{2}{4} (x - 0) + 0, y = - \frac{2}{4} (x - 0) + 0

Refine

y = \frac{x}{2}, y = - \frac{x}{2}

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

(\frac{x - 3}{4})^{2} - (\frac{y - 1}{3})^{2} = 1

x^{2} - y^{2} - 4 x - 6 y - 14 = 0

4 x^{2} - 9 y^{2} - 8 x + 72 y - 176 = 0

\frac{y ^{2}}{49} - \frac{x ^{2}}{64} = 1

What is the asymptotes of (y^2)/4-(x^2)/(16)=1 ?
The asymptotes of (y^2)/4-(x^2)/(16)=1 is y= x/2 ,\quad y=-x/2