What is the asymptotes of (y^2)/(16)-(x^2)/(25)=1 ?

The asymptotes of (y^2)/(16)-(x^2)/(25)=1 is y=(4x)/5 ,\quad y=-(4x)/5

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asymptotes of (y^2)/(16)-(x^2)/(25)=1

asymptotes

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

y = \frac{4 x}{5}, y = - \frac{4 x}{5}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 5

y = \frac{4}{5} (x - 0) + 0, y = - \frac{4}{5} (x - 0) + 0

Refine

y = \frac{4 x}{5}, y = - \frac{4 x}{5}

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

\frac{y ^{2}}{64} - \frac{x ^{2}}{9} = 1

x^{2} - y^{2} = 4

x^{2} - y^{2} + 8 x - 2 y + 14 = 0

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

What is the asymptotes of (y^2)/(16)-(x^2)/(25)=1 ?
The asymptotes of (y^2)/(16)-(x^2)/(25)=1 is y=(4x)/5 ,\quad y=-(4x)/5