What is the foci (y^2)/(25)-(x^2)/(11)=1 ?

The foci (y^2)/(25)-(x^2)/(11)=1 is (0,6),(0,-6)

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foci (y^2)/(25)-(x^2)/(11)=1

foci

\frac{y ^{2}}{25} - \frac{x ^{2}}{11} = 1

(0, 6), (0, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{11} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 11

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 11^{2} : 6

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

\frac{( y ) ^{2}}{121} - \frac{( x ) ^{2}}{81} = 1

8 x^{2} - 3 y^{2} = 24

\frac{( y ) ^{2}}{40} - \frac{( x ) ^{2}}{81} = 1

+ 9 x^{2} - 16 y^{2} = 144

\frac{x ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

What is the foci (y^2)/(25)-(x^2)/(11)=1 ?
The foci (y^2)/(25)-(x^2)/(11)=1 is (0,6),(0,-6)