What is the foci (y^2)/(225)-(x^2)/(324)=1 ?

The foci (y^2)/(225)-(x^2)/(324)=1 is (0,3sqrt(61)),(0,-3sqrt(61))

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foci (y^2)/(225)-(x^2)/(324)=1

foci

\frac{y ^{2}}{225} - \frac{x ^{2}}{324} = 1

(0, 361), (0, - 361)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{225} - \frac{x ^{2}}{324} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 15, b = 18

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 5^{2} + 1 8^{2} : 361

(0, 0 + 361), (0, 0 - 361)

Refine

(0, 361), (0, - 361)

- x^{2} + 8 x + 4 y^{2} - 40 y + 88 = 0

\frac{( y + 2 ) ^{2}}{36} - x^{2} = 1

\frac{x ^{2}}{23} - \frac{y ^{2}}{2} = 1

9 x^{2} - 16 y^{2} - 18 x + 64 y - 199 = 0

49 y^{2} - 100 x^{2} = 4900

What is the foci (y^2)/(225)-(x^2)/(324)=1 ?
The foci (y^2)/(225)-(x^2)/(324)=1 is (0,3sqrt(61)),(0,-3sqrt(61))