What is the foci (y^2)/(25)-(x^2)/(39)=1 ?

The foci (y^2)/(25)-(x^2)/(39)=1 is (0,8),(0,-8)

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foci (y^2)/(25)-(x^2)/(39)=1

foci

\frac{y ^{2}}{25} - \frac{x ^{2}}{39} = 1

(0, 8), (0, - 8)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{39} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 39

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 39^{2} : 8

(0, 0 + 8), (0, 0 - 8)

Refine

(0, 8), (0, - 8)

16 y^{2} - 25 x^{2} = 1600

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{16} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{4} = 1

\frac{( y + 2 ) ^{2}}{16} - \frac{( x - 3 ) ^{2}}{9} = 1

\frac{x ^{2}}{100} - \frac{y ^{2}}{49} = 1

What is the foci (y^2)/(25)-(x^2)/(39)=1 ?
The foci (y^2)/(25)-(x^2)/(39)=1 is (0,8),(0,-8)