What is the foci 3=x^2-y^2 ?

The foci 3=x^2-y^2 is (sqrt(6),0),(-sqrt(6),0)

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foci 3=x^2-y^2

foci

3 = x^{2} - y^{2}

(6, 0), (- 6, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

3 = x^{2} - y^{2} :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 3^{2} : 6

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

4 x^{2} - 9 y^{2} - 8 x + 72 y - 176 = 0

- x^{2} + 4 y^{2} - 8 y - 12 = 0

3 y^{2} - 12 x^{2} - 36 y - 48 x + 48 = 0

\frac{y ^{2}}{16} - \frac{x ^{2}}{20} = 1

\frac{( y + 5 ) ^{2}}{64} - \frac{( x + 2 ) ^{2}}{36} = 1