What is the foci (y^2)/(10)-((x-1)^2)/(10)=1 ?

The foci (y^2)/(10)-((x-1)^2)/(10)=1 is (1,2sqrt(5)),(1,-2sqrt(5))

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foci (y^2)/(10)-((x-1)^2)/(10)=1

foci

\frac{y ^{2}}{10} - \frac{( x - 1 ) ^{2}}{10} = 1

(1, 25), (1, - 25)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{10} - \frac{( x - 1 ) ^{2}}{10} = 1 :

Up-down Hyperbola with

(h, k) = (1, 0), a = 10, b = 10

(1, 0 + c), (1, 0 - c)

Compute

c :

c = 10^{2} + 10^{2} : 25

(1, 0 + 25), (1, 0 - 25)

Refine

(1, 25), (1, - 25)

- 4 x^{2} + y^{2} + 6 y - 27 = 0

4 y^{2} - 9 x^{2} + 8 y - 54 x - 113 = 0

9 x^{2} - 4 y^{2} = 1

\frac{( x - 7 ) ^{2}}{100} - \frac{( y + 8 ) ^{2}}{25} = 1

\frac{x ^{2}}{4} - (\frac{y + 1}{16})^{2} = 1

What is the foci (y^2)/(10)-((x-1)^2)/(10)=1 ?
The foci (y^2)/(10)-((x-1)^2)/(10)=1 is (1,2sqrt(5)),(1,-2sqrt(5))