What is the foci 4y^2-9x^2+16y+18x=29 ?

The foci 4y^2-9x^2+16y+18x=29 is (1,-2+sqrt(13)),(1,-2-sqrt(13))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 4y^2-9x^2+16y+18x=29

foci

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

(1, - 2 + 13), (1, - 2 - 13)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29 :

Up-down Hyperbola with

(h, k) = (1, - 2), a = 3, b = 2

(1, - 2 + c), (1, - 2 - c)

Compute

c :

c = 3^{2} + 2^{2} : 13

(1, - 2 + 13), (1, - 2 - 13)

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 6 ) ^{2}}{81} = 1

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

x^{2} - y^{2} = 13

\frac{( y ) ^{2}}{81} - \frac{( x ) ^{2}}{121} = 1

x^{2} - y^{2} = 15

What is the foci 4y^2-9x^2+16y+18x=29 ?
The foci 4y^2-9x^2+16y+18x=29 is (1,-2+sqrt(13)),(1,-2-sqrt(13))