What is the foci (x^2)/(81)-(y^2)/(16^2)=1 ?

The foci (x^2)/(81)-(y^2)/(16^2)=1 is (sqrt(337),0),(-sqrt(337),0)

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foci (x^2)/(81)-(y^2)/(16^2)=1

foci

\frac{x ^{2}}{81} - \frac{y ^{2}}{1 6 ^{2}} = 1

(337, 0), (- 337, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{81} - \frac{y ^{2}}{1 6 ^{2}} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 9, b = 16

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} + 1 6^{2} : 337

(0 + 337, 0), (0 - 337, 0)

Refine

(337, 0), (- 337, 0)

9 x^{2} - 4 y^{2} + 72 x + 180 = 0

1 = x^{2} - y^{2}

\frac{x ^{2}}{900} - \frac{y ^{2}}{1600} = 1

y^{2} - 9 x^{2} = 9

10 y^{2} - 5 x^{2} = 50

What is the foci (x^2)/(81)-(y^2)/(16^2)=1 ?
The foci (x^2)/(81)-(y^2)/(16^2)=1 is (sqrt(337),0),(-sqrt(337),0)