What is the foci (x^2)/5-(y^2)/7 =1 ?

The foci (x^2)/5-(y^2)/7 =1 is (2sqrt(3),0),(-2sqrt(3),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/5-(y^2)/7 =1

foci

\frac{x ^{2}}{5} - \frac{y ^{2}}{7} = 1

(23, 0), (- 23, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{5} - \frac{y ^{2}}{7} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + 7^{2} : 23

(0 + 23, 0), (0 - 23, 0)

Refine

(23, 0), (- 23, 0)

\frac{( x - 6 ) ^{2}}{25} - \frac{( y + 4 ) ^{2}}{9} = 1

3 x^{2} - 2 y^{2} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{25} = 1

\frac{( x - 6 ) ^{2}}{10} - \frac{( y + 2 ) ^{2}}{17} = 1

\frac{( x - 1 ) ^{2}}{1 2 ^{2}} - \frac{( y - 11 ) ^{2}}{8 ^{2}} = 1

What is the foci (x^2)/5-(y^2)/7 =1 ?
The foci (x^2)/5-(y^2)/7 =1 is (2sqrt(3),0),(-2sqrt(3),0)