What is the foci (y^2)/(25)-(x^2)/(49)=1 ?

The foci (y^2)/(25)-(x^2)/(49)=1 is (0,sqrt(74)),(0,-sqrt(74))

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foci (y^2)/(25)-(x^2)/(49)=1

foci

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

(0, 74), (0, - 74)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 7

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 7^{2} : 74

(0, 0 + 74), (0, 0 - 74)

Refine

(0, 74), (0, - 74)

- 9 x^{2} + y^{2} + 54 x - 117 = 0

\frac{( y ^{2} )}{27} - \frac{( x ^{2} )}{9} = 1

64 x^{2} - 100 y^{2} = 6400

(\frac{( x ^{2} )}{27}) - \frac{( ( y - 3 ) ^{2} )}{36} = 1

\frac{( x - 7 ) ^{2}}{25} - \frac{y ^{2}}{16} = 1

What is the foci (y^2)/(25)-(x^2)/(49)=1 ?
The foci (y^2)/(25)-(x^2)/(49)=1 is (0,sqrt(74)),(0,-sqrt(74))