What is the foci (x^2}{25}-\frac{y^2)/4 =1 ?

The foci (x^2}{25}-\frac{y^2)/4 =1 is (sqrt(29),0),(-sqrt(29),0)

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foci (x^2}{25}-\frac{y^2)/4 =1

foci

\frac{x ^{2}}{25} - \frac{y ^{2}}{4} = 1

(29, 0), (- 29, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{25} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + 2^{2} : 29

(0 + 29, 0), (0 - 29, 0)

Refine

(29, 0), (- 29, 0)

4 y^{2} - x^{2} + 6 x + 8 y + 4 = 0

- 9 x^{2} + y^{2} + 6 y - 27 = 0

x^{2} - 4 y^{2} - 8 = 0

\frac{( y + 1 ) ^{2}}{49} - \frac{( x + 3 ) ^{2}}{64} = 1

289 y^{2} - x^{2} = 1

What is the foci (x^2}{25}-\frac{y^2)/4 =1 ?
The foci (x^2}{25}-\frac{y^2)/4 =1 is (sqrt(29),0),(-sqrt(29),0)