What is the foci 4y^2-16x^2=64 ?

The foci 4y^2-16x^2=64 is (0,2sqrt(5)),(0,-2sqrt(5))

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foci 4y^2-16x^2=64

foci

4 y^{2} - 16 x^{2} = 64

(0, 25), (0, - 25)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

4 y^{2} - 16 x^{2} = 64 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} + 2^{2} : 25

(0, 0 + 25), (0, 0 - 25)

Refine

(0, 25), (0, - 25)

y^{2} - 9 x^{2} - 36 x - 8 y - 29 = 0

x^{2} - y^{2} - 4 x - 2 y - 13 = 0

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{22} = 1

\frac{x ^{2}}{16 + ( y - 4 ) ^{2}} = 1

\frac{( x - 2 ) ^{2}}{16} - \frac{( y + 3 ) ^{2}}{1} = 1

What is the foci 4y^2-16x^2=64 ?
The foci 4y^2-16x^2=64 is (0,2sqrt(5)),(0,-2sqrt(5))