What is the foci 9x^2-4y^2+18x-27=0 ?

The foci 9x^2-4y^2+18x-27=0 is (-1+sqrt(13),0),(-1-sqrt(13),0)

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foci 9x^2-4y^2+18x-27=0

foci

9 x^{2} - 4 y^{2} + 18 x - 27 = 0

(- 1 + 13, 0), (- 1 - 13, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 4 y^{2} + 18 x - 27 = 0 :

Right-left Hyperbola with

(h, k) = (- 1, 0), a = 2, b = 3

(- 1 + c, 0), (- 1 - c, 0)

Compute

c :

c = 2^{2} + 3^{2} : 13

(- 1 + 13, 0), (- 1 - 13, 0)

\frac{x ^{2}}{8} - \frac{y ^{2}}{8} = 1

\frac{y ^{2}}{64} - \frac{x ^{2}}{49} = 1

+ \frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

- 4 x^{2} + y^{2} = 36

\frac{y ^{2}}{4} - \frac{x ^{2}}{21} = 1

What is the foci 9x^2-4y^2+18x-27=0 ?
The foci 9x^2-4y^2+18x-27=0 is (-1+sqrt(13),0),(-1-sqrt(13),0)