What is the foci 9y^2-16x^2=81 ?

The foci 9y^2-16x^2=81 is (0, 15/4),(0,-15/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 9y^2-16x^2=81

foci

9 y^{2} - 16 x^{2} = 81

(0, \frac{15}{4}), (0, - \frac{15}{4})

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

9 y^{2} - 16 x^{2} = 81 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = \frac{9}{4}

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 3^{2} + (\frac{9}{4})^{2} : \frac{15}{4}

(0, 0 + \frac{15}{4}), (0, 0 - \frac{15}{4})

Refine

(0, \frac{15}{4}), (0, - \frac{15}{4})

9 x^{2} - 36 x - 4 y^{2} = 0

\frac{y ^{2}}{6} - \frac{x ^{2}}{6} = 1

x^{2} - y^{2} - 2 x - 6 y - 12 = 0

- \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

4 x^{2} - 9 y^{2} = 144