What is the foci (x^2}{49}-\frac{y^2)/4 =1 ?

The foci (x^2}{49}-\frac{y^2)/4 =1 is (sqrt(53),0),(-sqrt(53),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2}{49}-\frac{y^2)/4 =1

foci

\frac{x ^{2}}{49} - \frac{y ^{2}}{4} = 1

(53, 0), (- 53, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{49} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 7, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} + 2^{2} : 53

(0 + 53, 0), (0 - 53, 0)

Refine

(53, 0), (- 53, 0)

\frac{( y + \frac{7}{2} ) ^{2}}{25} - \frac{( x - \frac{9}{2} ) ^{2}}{25} = 1

y^{2} - 4 x^{2} = 16

\frac{y ^{2}}{4 ^{2}} - \frac{x ^{2}}{3 ^{2}} = 1

x^{2} - \frac{y ^{2}}{25} = 1

x^{2} - 9 y^{2} = 144

What is the foci (x^2}{49}-\frac{y^2)/4 =1 ?
The foci (x^2}{49}-\frac{y^2)/4 =1 is (sqrt(53),0),(-sqrt(53),0)