5y=x^2

Lösung

5 y = x^{2}

(h, k) = (0, 0), p = \frac{5}{4}

Schritte zur Lösung

5 y = x^{2}

Rewrite

5 y = x^{2}

in the standard form:

4 \cdot \frac{5}{4} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{5}{4}

x^{2} - 4 x = y + 4

(y + 2)^{2} = 12 x

- f (x) = 3 x^{2} + 2 x - 3

y^{2} - 4 y - 8 x + 20 = 0

y^{2} - 4 x - 6 y = - 1