What is the foci (x^2)/4-y^2=1 ?

The foci (x^2)/4-y^2=1 is (sqrt(5),0),(-sqrt(5),0)

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foci (x^2)/4-y^2=1

foci

\frac{x ^{2}}{4} - y^{2} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - y^{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 1

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 1^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

\frac{y ^{2}}{25} - x^{2} = 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{48} = 1

\frac{( y - 1 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{16} = 1

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{18} = 1

\frac{( y - 3 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{27} = 1

What is the foci (x^2)/4-y^2=1 ?
The foci (x^2)/4-y^2=1 is (sqrt(5),0),(-sqrt(5),0)