What is the foci 12x^2-3y^2=36 ?

The foci 12x^2-3y^2=36 is (sqrt(15),0),(-sqrt(15),0)

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foci 12x^2-3y^2=36

foci

12 x^{2} - 3 y^{2} = 36

(15, 0), (- 15, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

12 x^{2} - 3 y^{2} = 36 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 23

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + (23)^{2} : 15

(0 + 15, 0), (0 - 15, 0)

Refine

(15, 0), (- 15, 0)

\frac{y ^{2}}{4} - \frac{x ^{2}}{36} = 1

64 y^{2} - 36 x^{2} = 2304

\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

4 y^{2} - x^{2} + 2 x + 16 y + 7 = 0

\frac{( y + 6 ) ^{2}}{36} - \frac{( x + 4 ) ^{2}}{48} = 1

What is the foci 12x^2-3y^2=36 ?
The foci 12x^2-3y^2=36 is (sqrt(15),0),(-sqrt(15),0)